daver2
10k Member
The OP was considering buying one of this little €20 oscilloscopes. I ordered one and it arrived yesterday. If the OP ordered one today, it would be with him by the end of the week.
Dave
Dave
I suspect some type of oscillation.
Dwight
Now i ve connected again central pin of Vr on board...
i ve measured Q11,12 AND 13 collectors and i ve these measures:
Q11=14v
Q12=0v
Q13=14v
We have clearly all fallen into a parallel universe where the Laws of Physics are different!
Thanks for your patience....
now i am seeing Q14 (mje13006).... this transistor have central pin cut off...only two laterl pins are soldered on board....
it's correct?
In these 2 lateral pins i measure 0V...
on C16 always 14V
Unfortunately i don't have a 13006 spare...can i use equivalent?
Yes there are the equivalent parts noted on the circuit diagram.
But I would think it would be better to get the original part. These days there are a lot of copy & fake transistors. However, the fakes seldom (if ever) have gold plated lead wires.
If it was my monitor and I was wanting a genuine replacement part I would go for these, they are not expensive, so buy three of them to have some spares in case of accidents. I'm pretty sure these are genuine Motorola parts, but obviously you will have to wait the time for the post to get them:
https://www.ebay.co.uk/itm/2-count-...607913&hash=item2edbf9bc48:g:7FAAAMXQZ7dTlye8
Often,the central pin is cut off, because it connects to the metal tab that screws the transistor down (the collector connection) and the connection to the transistors's collector is via the screw that secures it.
While you are waiting for these transistors to arrive, you can get on with the fault finding.
Thanks, but it's normal have 0V to Q14?
Yes, currently you should measure 0V on the base and emitter pins of Q14. The collector (its metal tab and cut off center pin) with have the power supply voltage on it, that passes from the +12V rail via inductor L1, through the horizontal output transformer primary to the collector of Q14. So, I'm sure if you check on the metal tab of Q14, it will measure about 14V that you have been measuring elsewhere.
Obviously, the emitter of Q14 will always measure zero volts, its connected to negative or ground or "common".
The Base connection of Q14, is driven by the transformer T1. Currently there is no power applied to T1 (remember you have disconnected Q13's collector wire and have that connected via the 470R resistor to the 12V rail. So there cannot be any base voltage on Q14). It is better to leave it like that for now until the horizontal drive voltage from the computer board can be made to be normal and Q11,Q12 & Q13 are checked & Q14 replaced, before re-connecting Q13's collector to the driver transformer T1.
Until Dwight 'wakes up' and continues with the question 'why have we got +14V instead of +12V' - and if you want to power the PET up, then can you use your logic probe again (but fairly quickly) on the following points:
C16:
Q11 collector:
Q12 collector:
Q13 collector:
And tell us if there are pulses at each point or not please.
This assumes we have the 470 Ohm resistor in the collector of Q13 to +12(14) Volts - instead of transformer T1?
Switch the PET off after the test, report the results and wait for Dwight...
Regards,
Dave
I assume you have the monitor connected to the PET main board?
If so, you are not getting any HORIZONTAL DRIVE signal from the PET main board again. That is the only way I can think of that C16 would be HIGH.
Also, if Q11 collector is LOW, this should turn ON transistor Q12 and its collector should be +12(14) Volts.
Let's wait for Dwight. What I would like to propose next (unless Dwight has a better idea) is to get some high-quality, close up photographs of the front and rear of the monitor PCB if that is possible. You will have to post the photographs on a file-sharing site, and link us to them. I would like to see if this PCB has been modified at all...
Dave